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Integral of (8x+4)/(4x^2+4x)

\int\frac{8x+4}{4x^2+4x}dx

Step by step solution

Problem

$\int\frac{8x+4}{4x^2+4x}dx$

Show full step-by-step solution

Answer

$\int\frac{u}{\left(\frac{1}{2}+\frac{1}{16}\left(u-4\right)\right)\left(u-4\right)}du$

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$\int\frac{8x+4}{4x^2+4x}dx$

Main topic:

Integration by substitution

Used formulas:

3. See formulas

Time to solve it:

0.59 seconds