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We need to isolate the dependent variable $y$, we can do that by simultaneously subtracting $\sqrt{2y+3}$ from both sides of the equation
Learn how to solve integrals of rational functions problems step by step online.
$\sqrt{2y+1}=1-\sqrt{2y+3}$
Learn how to solve integrals of rational functions problems step by step online. Solve the equation with radicals (2y+1)^1/2+(2y+3)^1/2=1. We need to isolate the dependent variable y, we can do that by simultaneously subtracting \sqrt{2y+3} from both sides of the equation. Removing the variable's exponent raising both sides of the equation to the power of 2. Expand \left(1-\sqrt{2y+3}\right)^{2}. Add the values 1 and 3.