Final Answer
$y=\ln\left(e^{4x}-1\right)-\ln\left(e^{4x}+1\right)$
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Step-by-step Solution
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The logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator
$y=\ln\left(e^{4x}-1\right)-\ln\left(e^{4x}+1\right)$
Final Answer
$y=\ln\left(e^{4x}-1\right)-\ln\left(e^{4x}+1\right)$