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Step-by-step Solution

Solve $\frac{x^4-1\left(\frac{4}{3}\right)x^3-2x^2-1\left(\frac{4}{3}\right)x+1}{x-2}$

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Answer

$\frac{\left(x^{2}-1\right)^{2}-\frac{4}{3}x^3-\frac{4}{3}x}{x-2}$

Step-by-step explanation

Problem to solve:

$\frac{x^4-\frac{4}{3} x^3-2x^2-\frac{4}{3}\cdot x+1}{x-2}$
1

Divide $4$ by $3$

$\frac{x^4-1\cdot \frac{4}{3}x^3-2x^2-1\cdot \frac{4}{3}x+1}{x-2}$
2

Apply the formula: $-x$, where $x=\frac{4}{3}$

$\frac{x^4-\frac{4}{3}x^3-2x^2-1\cdot \frac{4}{3}x+1}{x-2}$

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Answer

$\frac{\left(x^{2}-1\right)^{2}-\frac{4}{3}x^3-\frac{4}{3}x}{x-2}$
$\frac{x^4-\frac{4}{3} x^3-2x^2-\frac{4}{3}\cdot x+1}{x-2}$

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Time to solve it:

~ 0.82 seconds

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