$x^2=108-3x$
$\frac{\left(-15\right).\left(-6\right)}{\left(-5\right)}$
$\frac{-0}{0+1}$
$-4x^2+2x=-1$
$\int_0^{\pi}\left(tan^6\left(3x\right)\right)dx$
$\lim_{x\to-\infty}\left(\frac{3x^2}{2x+3}\right)$
$3\left(-9q+9\right)+3\left(8q-3\right)$
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