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Solve the trigonometric equation $1-\cos\left(4x\right)=8\cos\left(x\right)\sin\left(2x^2\right)$

Step-by-step Solution

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Final Answer

$x=\frac{1}{2}\pi+2\pi n,\:x=\frac{3}{2}\pi+2\pi n,\:x=0\:,\:\:n\in\Z$
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Step-by-step Solution

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Use the trigonometric identity: $1-\cos\left(2x\right)=2\sin\left(x\right)^2$

$2\sin\left(2x\right)^2=8\cos\left(x\right)\sin\left(2x^2\right)$

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$2\sin\left(2x\right)^2=8\cos\left(x\right)\sin\left(2x^2\right)$

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Learn how to solve problems step by step online. Solve the trigonometric equation 1-cos(4x)=8cos(x)sin(2x^2). Use the trigonometric identity: 1-\cos\left(2x\right)=2\sin\left(x\right)^2. Grouping all terms to the left side of the equation. Using the sine double-angle identity: \sin\left(2\theta\right)=2\sin\left(\theta\right)\cos\left(\theta\right). The power of a product is equal to the product of it's factors raised to the same power.

Final Answer

$x=\frac{1}{2}\pi+2\pi n,\:x=\frac{3}{2}\pi+2\pi n,\:x=0\:,\:\:n\in\Z$

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Function Plot

Plotting: $1-\cos\left(4x\right)-8\cos\left(x\right)\sin\left(2x^2\right)$

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0
a
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f
g
m
n
u
v
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x
y
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.
(◻)
+
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×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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