$\lim_{x\to3}\left(\frac{5x^2-16x+3}{x^2-6x+9}\right)$
$\sqrt{0.04}0.2^2$
$5x-4\:>7x+2$
$\lim_{x\to\infty}\left(\ln\left(x\right)-\ln\left(1\right)\right)$
$\int_1^{\infty}\left(\frac{5}{x^6}\right)dx$
$\frac{1}{2}860\cdot13.92^2$
$\left(-8\right)^6$
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