$5^{x+6}=125$
$\frac{40^9}{40^3}$
$\sqrt{-169}$
$y-2^3$
$\left(-8\right)-\left(-1\right)-\left(+3\right)+\left(-5\right)+\left(+9\right)$
$1-4sin^2x$
$\int\sqrt{8x^2-4}dx$
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