$\left(x^2-6x\right)^2-2\left(2x^2-3x\right)\left(2x^2-3\right)$
$\int ln\left(x+6\right)dx$
$x^2+2x=-1$
$-40\:\:50\:+\:-30$
$\lim_{x\to2}\left(\frac{x^2+3x-10}{x^3+2x^2+x-2}\right)$
$6.25\cdot10^6$
$vt-25t^2$
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