$\int_0^{\infty}40x^3e^{-x}\:dx$
$7ab^2+21a^3b+14a^2b^3$
$\left(\frac{-2a^{2}}{b^{5}}\right)^{2}$
$\int cosbx\:dx$
$-3-2\left(5+1\right)$
$\int3\cdot\:\left(x^2+1\right)^2dx$
$\sqrt[4]{0.18}$
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