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Solve the equation $\left(x+3\right)^2+\left(y-4\right)^2=21$

Step-by-step Solution

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Final Answer

$y=4+\sqrt{21-\left(x+3\right)^2},\:y=4-\sqrt{21-\left(x+3\right)^2}$
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Step-by-step Solution

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We need to isolate the dependent variable , we can do that by simultaneously subtracting $\left(x+3\right)^2$ from both sides of the equation

$\left(y-4\right)^2=21-\left(x+3\right)^2$

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$\left(y-4\right)^2=21-\left(x+3\right)^2$

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Learn how to solve problems step by step online. Solve the equation (x+3)^2+(y-4)^2=21. We need to isolate the dependent variable , we can do that by simultaneously subtracting \left(x+3\right)^2 from both sides of the equation. Removing the variable's exponent. Cancel exponents 2 and \frac{1}{2}. We need to isolate the dependent variable , we can do that by simultaneously subtracting -4 from both sides of the equation.

Final Answer

$y=4+\sqrt{21-\left(x+3\right)^2},\:y=4-\sqrt{21-\left(x+3\right)^2}$

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Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

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Function Plot

Plotting: $\left(x+3\right)^2+\left(y-4\right)^2-21$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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