$tan^8x$
$3=\sin\left(2x\right)$
$10-x-3x+27$
$-3x^2\left(2a-3b+4z^2\right)$
$\frac{1^2-1}{1^3+3\left(1\right)-4}$
$\sqrt[14]{\frac{100a^{10}}{9b^6}}$
$x^2+-6>0$
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