Solve the equation 3+3x+(10x)/5=2(x-2)-4

\frac{10x}{5}+3+3x=2\left(x-2\right)-4

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Answer

$x=-\frac{11}{21}$

Step by step solution

Problem

$\frac{10x}{5}+3+3x=2\left(x-2\right)-4$
1

Apply the formula: $\frac{b\cdot a}{c}$$=b\frac{a}{c}$, where $a=10$, $b=x$ and $c=5$

$3x+3+10\cdot 2x=2\left(x-2\right)-4$
2

Multiply $2$ times $10$

$3x+3+20x=2\left(x-2\right)-4$
3

Adding $20x$ and $3x$

$3+23x=2\left(x-2\right)-4$
4

Multiply $\left(x+-2\right)$ by $2$

$3+23x=-4-4+2x$
5

Subtract the values $-4$ and $-4$

$3+23x=2x-8$
6

Grouping terms

$-2x+3+23x=-8$
7

Adding $23x$ and $-2x$

$3+21x=-8$
8

Subtract $3$ from both sides of the equation

$21x=-8-3$
9

Subtract the values $-8$ and $-3$

$21x=-11$
10

Multiply both sides of the equation by $$

$x=-\frac{11}{21}$

Answer

$x=-\frac{11}{21}$

Problem Analysis

Main topic:

Polynomials

Time to solve it:

0.29 seconds

Views:

87