$\frac{3}{x+2}=\frac{5}{x-4}$
$2x-8>3x+2$
$7x+5=3x-15$
$\frac{8}{1}\cdot12$
$\tan x=-1$
$\left(6m^3+3n^2\right)^3$
$\frac{dy}{dx}+y=x\cdot y^3$
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