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Integrate -1(16+x^2)^0.5*11 from -41*1 to 1

\int_{\left(-41\cdot1\right)}^{1}11\left(-1\right)\sqrt{16+x^2}dx

Step by step solution

Problem

$\int_{\left(-41\cdot1\right)}^{1}11\left(-1\right)\sqrt{16+x^2}dx$

Show full step-by-step solution

Answer

$-11\int_{-41}^{1}\frac{d}{d\theta}\left(4\tan\left(\theta\right)\right)\sec\left(\theta\right)d\theta$
$\int_{\left(-41\cdot1\right)}^{1}11\left(-1\right)\sqrt{16+x^2}dx$

Main topic:

Integration by trigonometric substitution

Used formulas:

1. See formulas

Time to solve it:

0.47 seconds