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{\frac{\left(x+2\right)\left(x+2\right)}{6}}\geq {\frac{x}{3}+\frac{1}{2}}

Solve the inequality ((x+2)(x+2))/6%x/3+1/2

Answer

$\frac{4+4x+x^2}{6}-\frac{1}{3}x\geq \frac{1}{2}$

Step-by-step explanation

Problem

${\frac{\left(x+2\right)\left(x+2\right)}{6}}\geq {\frac{x}{3}+\frac{1}{2}}$
1

When multiplying exponents with same base you can add the exponents

$\frac{\left(2+x\right)^2}{6}\geq \frac{1}{2}+\frac{x}{3}$

Unlock this step-by-step solution!

Answer

$\frac{4+4x+x^2}{6}-\frac{1}{3}x\geq \frac{1}{2}$