Step-by-step Solution

Solve the equation x^2+x+2=113

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$x_1=10.1419,\:x_2=-11.1419$

Step-by-step explanation

Problem to solve:

$x^2+x+2=113$
1

Rewrite the equation

$x^2+x-113=0$
2

To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where $a=1$, $b=1$ and $c=-113$

$x =\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x_1=10.1419,\:x_2=-11.1419$
$x^2+x+2=113$