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Rewrite the fraction $\frac{-4x^2-25x+41}{\left(x+4\right)\left(4x-5\right)\left(2x-3\right)}$ in $3$ simpler fractions using partial fraction decomposition
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$\frac{-4x^2-25x+41}{\left(x+4\right)\left(4x-5\right)\left(2x-3\right)}=\frac{A}{x+4}+\frac{B}{4x-5}+\frac{C}{2x-3}$
Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int((-4x^2-25x+41)/((x+4)(4x-5)(2x-3)))dx. Rewrite the fraction \frac{-4x^2-25x+41}{\left(x+4\right)\left(4x-5\right)\left(2x-3\right)} in 3 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by \left(x+4\right)\left(4x-5\right)\left(2x-3\right). Multiplying polynomials. Simplifying.