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\frac{d^2}{dx^2}\left(\left(x-1\right)^3\right)\left(x-3\right)

Find the higher order derivative of (x-1)^3

Answer

$\left(x-3\right)\frac{d}{dx}\left(1+\frac{d}{dx}\left(-1+x^2\left(x-1\right)-2x\left(x-1\right)\right)\right)$

Step-by-step explanation

Problem to solve:

$\frac{d^2}{dx^2}\left(\left(x-1\right)^3\right)\left(x-3\right)$
1

Apply the rule of the cube of a binomial

$\left(x-3\right)\frac{d^2}{dx^2}\left(\left(x-1\right)\left(x^2-2x+1\right)\right)$

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Answer

$\left(x-3\right)\frac{d}{dx}\left(1+\frac{d}{dx}\left(-1+x^2\left(x-1\right)-2x\left(x-1\right)\right)\right)$

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$\frac{d^2}{dx^2}\left(\left(x-1\right)^3\right)\left(x-3\right)$

Main topic:

Differential calculus

Used formulas:

2. See formulas

Time to solve it:

~ 0.45 seconds