$2x=36$
$x^2-16x+29=0$
$\left(\frac{2}{3}x\:+\:\frac{5}{7}\right)^2$
$\int\frac{5x^4-8x^3+9x+7}{x^7}dx$
$\left(y^3m^{12}\right)^2$
$6\left(\sqrt[3]{54a^5}\right)\:-4a\left(\sqrt[3]{16a^2}\right)$
$y'+\frac{y}{x+1}=x$
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