$2x^2+5x+x^2+4+10$
$3-\:2x<\:2x\:+23$
$-12y+9y+4y$
$\left(4-9\right)+\:\left[2-\left(-5\right)\right]$
$\left(3x+1\right)^{\frac{1}{4}},\:x=0,\:x=8,\:y=0$
$x^2+y^2-7=0$
$\frac{2x}{5}=16$
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