$\frac{dy}{dx}=\frac{1}{1+cos\:x}$
$\frac{dy}{dx}=\frac{3x^{2}}{e^{2y}}$
$-y^2=x-3$
$\sqrt[4]{x^3\sqrt{x}}$
$\frac{1}{5}x^3-\frac{1}{2}x^2+\frac{1}{4}x$
$27\left(-24\right)$
$\left(3x^4-y^5\right)^2$
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