$\frac{2a-2}{2a^2-50}\cdot\:\frac{a^2-4a-5}{3a+3}$
$\left(2b-1\right)\left(4b^2+2b+1\right)$
$\left(2x^2-5y\right)^4$
$-4a=15-7a$
$\frac{4x^5+2x-1}{x-1}$
$16b^2-24$
$5b+4b$
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