$x^2-3x+1.5$
$7^6\cdot7^{-4}$
$\lim_{x\to\infty}\left(\frac{x^2-1}{x^3+4x-3}\right)$
$\ln\left(3x\right)+\ln\left(x+2\right)=\ln\left(9\right)$
$x^2+6x-52=0$
$-12+4\left(-4-\sqrt{6+10}\right)^2$
$x+86=47$
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