$cos^3x-cos\:x$
$\int\left(\frac{6x+7}{\left(x+1\right)^3\left(x+8\right)\left(x+7\right)}\right)dx$
$\frac{v+3}{v+10}=\frac{6}{5}$
$\log\left(4\:+\:x\right)\:-\:\log\left(x\:-\:4\right)\:=\:\log\left(3\right)$
$x^2+3x+9<0$
$8+4-6-9+19-12+15-99$
$2x-\frac{y}{7}+\frac{1}{3}=\frac{2}{3}$
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