$\lim_{x\to\infty}\left(\sqrt{x^2+3x}-\sqrt{x^2+4x}\right)$
$\lim_{x\to0}\:x^2\left(2x^6-3w^4\right)^{-1}$
$\left(3v+y^3x\right)^2$
$c+d-1=17$
$a^2-25\:$
$-\left(-15\right)-\left(-6\right)$
$25a^5b^4c-100a^5b^3c^4+150a^3b^3c^4$
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