$\lim_{x\to0}\left(\frac{ln\left(1+4x^2\right)}{x^2}\right)$
$\int\left(3x^4-1\right)x^3dx$
$12\cdot\left(-4\right)\cdot\left(-5\right)$
$\int10\left(5x+3\right)^2dx$
$x+3>16$
$-1+5-8+3-11$
$a\times\sqrt{1+1}$
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