$\left(2^3\right)\left(2\right)\left(2^3\right)$
$x\frac{dy}{dx}+4y=x^2-x$
$s2+34s+494$
$\left(-2x+6\right)^3$
$\left(5x^2y^3+3m^2\right)^2$
$\left(a^2+b^2+c^2\right)\left(a+b+c\right)\left(a^8+b^8+c^8\right)$
$\frac{6x^4+25x^3+18x^2-24x+4}{2x-1}$
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