$3x+\frac{1}{2}<7x+\frac{5}{2}$
$\int\:\frac{e^x}{10e^x+7}dx$
$x^4+6x^3+9x^2-4x-12$
$2u^3v^{-2}.\:2vu^2$
$\left(tan-cot\:\right)^3$
$-10\:-\:\left(6\:-\:16\right)\:-\:2$
$3x+2;x=1$
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