$\sqrt[4]{16x^{12}}$
$-3.6-1.9t+1.7+5.1t$
$4u^2+u-1$
$b0ca7a$
$\frac{2x}{4}=13$
$\lim_{x\to4}\frac{x^2-4}{x^2-x-12}$
$\int\left(2x\left(x^2+6\right)^8\right)dx$
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