$\cos^4\left(3x\right)-\sin^4\left(3x\right)=\cos\left(6x\right)$
$8x^3-5x+3.\:3x^3-4$
$4-2y;\:x=2;\:y=-1$
$11+-9+20+-3+-12+-1$
$2x^2-2xy$
$x^2-8x+10=0$
$\int\frac{\ln\left(x\right)}{7x^{\frac{4}{3}}}dx$
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