$4\cdot\frac{1}{2}\sqrt[3]{24\cdot3^2}$
$20 - 5 \cdot 4$
$585+495$
$\int x\left(6x^3+\sqrt{x}\right)dx$
$5\left(y-7\right)$
$-\left(7g+5.3\right)$
$2\:\frac{\left(\frac{1}{2}\right)}{\frac{1}{3^2}}$
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