$\left(3e^{2x}+6\right)^2$
$9f^2-6fg+g^2$
$\left(+3\right)\left(+3\right)\left(+3\right)\left(+3\right)\left(+3\right)$
$\left(-1.54\right)\cdot\left(-1.64\right)$
$10b\:-\:30ab2\:=\:0$
$2x^2-9x-81$
$\frac{2^x+3^x}{6^x}$
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