$\lim_{x\to0}\left(\frac{w^3-64w}{w^2+2w}\right)$
$3\left(11\right)^4-3\left(11\right)^3-\left(11\right)^2+3\left(11\right)-1\:$
$x^3-2x+1=1$
$\left(sinx\right)\left(cosx\:-sinx\right)$
$x^2+4z^2-6x-y+10=0$
$-199+-325$
$-8\:+\:x\:=\:-16$
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