$\left(\frac{4}{5}x^3+\frac{2}{3}y^4\right)^2$
$\:\left(2x.2x\right)+\left(2x+3.3\right)+\left(3.2x\right)$
$\frac{x^4-3x^3+2x-3\:}{x^3-2}$
$9a-b-2a-10b$
$\frac{2x}{x^2-4x-5}+\frac{7}{x^2+7x+6}$
$7\left(-3+12.8\right)$
$4.26\cdot8.4$
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