$xy'=y+2$
$a^3a^3$
$4m^6-16n^8$
$-6\:-3-3-6-4-5-2-4-2$
$\frac{dy}{dx}=7$
$\frac{dy}{dx}+6y=e^{-2x}$
$\int_0^1\left(\frac{1}{x^3-5x^2}\right)dx$
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