$\left(3x^3+y^3\right)^3$
$4\sqrt{\left(16\right)^5}$
$3-3+5-3\cdot4+3$
$\frac{3x^3-2x^2+3x-1}{x+1}$
$-4+-2n<-2$
$2\:\frac{1}{3}-\frac{2}{3}$
$12x+3y=6$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!