$\lim_{x\to1}\left(\frac{1}{\ln\left(x\right)}-\frac{1}{x}\right)$
$243-3a^2$
$8\cdot7+3$
$x+2x-7x+18x-4$
$\frac{x+1}{x}\ge3$
$y=\frac{x^5}{a+b}-\frac{x^2}{a-b}$
$\left(a-\sqrt{2b}\right)^2$
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