$\lim_{x\to0}\left(\frac{\left(6^x-5^x\right)}{\left(4^x-3^x\right)}\right)$
$\frac{dy}{dx}=\frac{\left(xy+4y-x-4\right)}{\left(xy-9y+x-9\right)}$
$-0.5x^2+2.5x+4.5$
$6\:\frac{3}{2}$
$\left(xy-3z\right)^3$
$1^0$
$5^{3}-t^{2}$
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