$\int\frac{x^2-1}{x+2}dx$

$\frac{x^4-4^4}{x-4}$

$\frac{d}{dx}\left(3sin\left(x+y\right)+3sin\left(x+z\right)+7sin\left(z+y\right)=0\right)$

$\left(36:6\right)-4+\left(-3\cdot5\right)$

$4\left(-3^2\right)^3$

$\int9^{4x+2}dx$

$\frac{3\left(4a+5c\right)}{2\left(-3b+2\right)};\:a=2;\:b=-2;\:c=1$