$\frac{5x}{2}=10$

$\frac{6x^2-2x^2}{2x}$

$\lim_{x\to3}\left(\frac{x^2-6x+24}{x^2-4x+3}\right)$

$\left(-3\right)^2\cdot\left(2\right)^3\cdot\left(5\left(-4\right)\right)^2$

$\left(x-3\right)^2-11\left(x-3\right)+30$

$\lim_{x\to0}\left(x+3\right)$

$3\log_b\left(4\right)+2\log_b\left(6\right)-8\log_b\left(2\right)$