$\left(3x^2+4x^3\right)^3$
$\sin^2x+5\cos^2x-3=0$
$\log\left(x^2+3\right)=\log\left(2\right)$
$2x\:-\:6\:+\:7x\:+\:8$
$\left(\frac{3}{4}a-b\right)^2$
$\frac{20a^2b^2}{8a^3b^3}$
$x\:+\:10\:\le15$
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