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Exercise

$\int_{2\sqrt{2}}^4\frac{1}{\left(x^3\sqrt{x^2-4}\right)}dx$

Final answer to the exercise

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Other solved exercises

$lnx+lny=\pi$

$\frac{dx}{dy}=\frac{3x^2}{y^2}$

$\frac{dy}{dx}=\ln6$

$\int x^2\sqrt[2]{x^3-4}dx$

$\frac{x^{2\:}-x+1\:}{x}$

$\sqrt{0.1}$

$v^2-36$
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