$\sqrt{17}\cdot\sqrt{6}$
$-4x-2\left(3x+4\right)+10$
$\frac{d}{dx}e^{2x^{5x}}$
$4x^7+6$
$\int\left(-e^x\right)sec^2\left(x\right)dx$
$\left(10b+4\right)+\left(6-9b\right)-\left(3b-7\right)+20+\left(-7+2x\right)-\left(3x-7\right)$
$\left(x+\frac{7}{4}\right)^2$
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