$\left|8\right|-\left|7\right|$
$x^2-225>0$
$\frac{3x^3-x^2+2}{x+2}$
$\left(12+9ab^3\right)\left(12-9ab\right)\left(2+a^2b\right)$
$\:\:\:\:\:\frac{k^5}{k^8}=\:\:\:\:\:\:\:\:\:\:$
$\left(3a\:+\:2\right)\:\left(3a\:-\:3\right)\:$
$\left(x^3-2\right)^4$
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