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Exercise

$y=\frac{\left(x^2-8\right)^{\frac{1}{3}}\sqrt{x^3+2}}{x^6-2x+1}$

Final answer to the exercise

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$250+8+2$

$\frac{1-\cot\left(x\right)}{\cot\left(x\right)}=\tan\left(x\right)-1$

$x2+3x-18=0$
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