$s^2-s+4$
$\left(4b^2-a^2b^2\right)^4$
$-7+\left(8\right)\left(-6\right)-5$
$x^3+3x^2-10x+6\:by\:\left(x+2\right)$
$3\sqrt{6\cdot3+10}$
$-\frac{2}{3}b+\frac{1}{5}-1+\frac{5}{6}b$
$\left(7a^2+5a+3\right)+\left(2a-3a^2-4\right)$
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