$24x+7x-8-16x+9x+14-4x+32x-22$
$\frac{\left(\frac{a}{b}+1\right)}{\frac{b}{a}-1}$
$-2+-4+7+456+568$
$\lim_{x\to-1}\left(\left(\frac{\left(x^4+9x^3+5x+13\right)}{x+1}\right)\right)$
$-\frac{23}{21\left(\infty\right)^{21}}$
$\int\frac{x^2+x+1}{x^3+7x}dx$
$\frac{5x+4}{2x-1}\ge2$
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