$6\sin\:\theta\:-1=0$
$8\left(8x-3\right)$
$x^2-10x-24=0$
$3x+5\le4x+3$
$\cot\:\left(\theta\:\right)=\frac{1}{\sqrt{sec^2\theta\:-1}}$
$m^2+24m+144$
$25b^2\:-\:4b\:+\:16$
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