$a^6-12ab+36^2$
$\left(a^3b^6+64\right)$
$2.^3+4.^2$
$4-\frac{x^2}{4}$
$\lim_{x\to3}\left(\frac{\left(x^2-9\right)}{\left|x-3\right|}\right)$
$f\left(x\right)=\frac{1}{4}\left(x^5-9x^3+4\right)\left(5x-\frac{6}{x}\right)$
$25x^2+15xy-10y$
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